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Which expression is equivalent to RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Baseline EndRoot? 2 a b c squared (RootIndex 3 StartRoot 4 a squared b cubed c EndRoot) 4 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot)15 x Superscript 6 Baseline y Superscript 8 Baseline (RootIndex 3 StartRoot x y EndRoot) 15 x cubed y Superscript 4 Baseline (RootIndex 3 StartRoot x y EndRoot) 8 x Superscript 6 Baseline y Superscript 8 Baseline (RootIndex 3 StartRoot x y EndRoot)D: The range of the function is all real numbers greater than or equal to 0. The square root of a negative number, such as \sqrt (-144) , is undefined. Explain why the square root of -x, \sqrt (-x), is not necessarily undefined and what this means about the domain and range of f (x) = \sqrt (-x). Sample Response: If x is a negative number, then ...

StartFraction 1 Over 2 pi StartRoot LC EndRoot EndFraction where f is in cycles per? second, L is in? henrys, and C is in farads. Find the resonant? frequency, to the nearest? thousand, of a circuit if Lequals 7.199 times 10 Superscript negative 4 henrys and Cequals 4.3 times 10 Superscript negative 11 farads.a. f (x) = 162 superscript startfraction x over 4 b. f (x) = (3 rootindex 4 startroot 2 endroot) superscript x c. f (x) = 9 rootindex 4 startroot 2 endroot superscript x d. f (x) = 126 superscript startfraction 4 over x e. f (x) = left-bracket 3 (2 superscript one-fourth baseline) right-bracket superscript xStep 1: Enter the radical expression below for which you want to calculate the square root. The square root calculator finds the square root of the given radical expression. If a given number is a perfect square, you will get a final answer in exact form. If a given number is not a perfect square, you will get a final answer in exact form and ...6/y^8. Anja simplified the expression 10x^-5/-5x^10 to 15/x^15. What mistake did Anja make? She subtracted the coefficients instead of dividing them. Describe how to simplify the expression 3^-6/3^-3. NOT Multiply the bases and then subtract the exponents. What is the quotient of -8x^6/4x^-3?

5 /5. heart. 3. verified. Verified answer. What is the simplified form of startroot startfraction 72 x superscript 16 baseline over 50 x superscript 36 baseline endfraction endroot? assume x ≠ 0. star. 5 /5. heart.This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Evaluate the following integral. Integral from nothing to nothing StartFraction dx Over StartRoot x squared minus 484 EndRoot EndFraction∫dxx2−484 , xgreater than>22 What substitution will be the most ... ….

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app.formative.comSimplify: StartRoot 64 r Superscript 8 Baseline EndRoot. star. 4.6/5. heart. 9. verified. Verified answer. ... What is the simplified form of startroot 64 x superscript 16 baseline endroot?8x48x832x432x8. verified. Verified answer. Jonathan and his sister Jennifer have a combined age of 48. If Jonathan is twice as old as his sister, …

16 answers. 1.1K people helped. report flag outlined. Answer: D. ... StartFraction 1 Over RootIndex 3 StartRoot x Superscript 5 Baseline EndRoot EndFraction Negative RootIndex 3 StartRoot x Superscript 5 Baseline EndRoot Negative RootIndex 5 StartRoot x cubed EndRoot. star. 4.5/5. heart. 77.16 Questions. Add This Formative. 5. 1. sin B = ? (fraction) visibility View Drawing. 5. 2 ...

timesanddemocrat newspaper The simplest form of √250c³/√9d⁶ is 5c√ 10c/3d³. What is Equation? Two or more expressions with an Equal sign is called as Equation. The given equation or expression is √(250c³/9d⁶). StartRoot StartFraction 250 c cubed Over 9 d Superscript 6 Baseline EndFraction EndRoot hair affinity chathamace spa eatontown reviews RootIndex 5 StartRoot 4 x squared EndRoot times RootIndex 5 StartRoot 4 x squared EndRoot 4 x squared RootIndex 5 StartRoot 16 x Superscript 4 Baseline EndRoot 2 (RootIndex 5 StartRoot 4 x squared EndRoot) 16 x Superscript 4. loading. See answers. loading. Ask AI. loading. ... (RootIndex 6 StartRoot x Superscript 5 Baseline EndRoot). star. 4.2 ...What is the simplified base for the function f(x) = 2RootIndex 3 StartRoot 27 EndRoot Superscript 2 x? 2 3 9 18. loading. See answers. loading. Ask AI. loading. report flag outlined. loading. bell outlined. Log in to add comment. Advertisement. Answer. 33 people found it helpful. hernandez2020f. hernandez2020f. Ambitious. 39 answers. cl11 pill Check all that apply. f (x) = 5 RootIndex 3 StartRoot 16 Endroot Superscript x Baseline = 5 (2 RootIndex 3 StartRoot 2 EndRoot) Superscript x f (x) = 2.3 (8) Superscript one-half x Baseline = 2.3 (4) Superscript x f (x) = 81 Superscript StartFraction x Over 4 EndFraction Baseline = 3 Superscript x f (x) = three-fourths StartRoot 27 EndRoot ...Precalculus questions and answers. Answer the questions about the following function. f left parenthesis x right parenthesis equals StartFraction x plus 12 Over x minus 8 EndFractionf (x)=x+12 x−8 (a) Is the point left parenthesis 2 comma negative 19 right parenthesis (2,−19) on the graph of f? (b) If x = 3 comma3, what is f (x)? upc 012381223619fullerton electricity outagelas marias tacos y pupusas Study with Quizlet and memorize flashcards containing terms like What is the simplified form of √72x^16/50x^36? Assume x ≠ 0. a) 6/5x^10 b) 6/5x^2 c) 6/5 x^10 d) 6/5 x^2, What is the simplified form of √144x^36 a)12x^6 b)12x^18 c)72x^6 d)72x^18, Use the graphing calculator to graph the function f(x)=√x. Which table of values contains points that lie on the graph of the function? and more. summerlin entrada Given that " Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, " It can be written as where The given expression is where female pec bouncingdodgers rs seatsus 89a road conditions Answer link. 4r^3 The trick is to look for squared value and then to take them outside the square root but not in squared form. Note that 16 = 4^2" and "r^6 = r^ (3xx2)= (r^3)^2 sqrt (16r^6)" "->" "sqrt (4^2 (r^3)^2)" "=" "4r^3 If you wished to be really fussy consider this example: (-2)xx (-2)" " =" " +4" " =" " (+2)xx (+2) So we have: sqrt ...2 (RootIndex 4 StartRoot 16 x EndRoot ) minus 2 (RootIndex 4 StartRoot 2 y EndRoot ) + 3 (RootIndex 4 StartRoot 81 x EndRoot ) minus 4 (RootIndex 4 StartRoot 32 y EndRoot ) There’s just one step to solve this. Expert-verified. Share Share.